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434200210441 = 1387393129619
BaseRepresentation
bin1100101000110000101…
…10010110110000001001
31112111202011022001220121
412110120112112300021
524103220223213231
6531245133223241
743240612615234
oct6243026266011
91474664261817
10434200210441
11158163776728
1270198931b21
1331c38c53b5a
141703039a41b
15b464144311
hex6518596c09

434200210441 has 4 divisors (see below), whose sum is σ = 434203478800. Its totient is φ = 434196942084.

The previous prime is 434200210397. The next prime is 434200210463. The reversal of 434200210441 is 144012002434.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 434200210441 - 27 = 434200210313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (434200210481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1426071 + ... + 1703548.

It is an arithmetic number, because the mean of its divisors is an integer number (108550869700).

Almost surely, 2434200210441 is an apocalyptic number.

It is an amenable number.

434200210441 is a deficient number, since it is larger than the sum of its proper divisors (3268359).

434200210441 is a wasteful number, since it uses less digits than its factorization.

434200210441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3268358.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 434200210441 its reverse (144012002434), we get a palindrome (578212212875).

The spelling of 434200210441 in words is "four hundred thirty-four billion, two hundred million, two hundred ten thousand, four hundred forty-one".

Divisors: 1 138739 3129619 434200210441