Base | Representation |
---|---|
bin | 1100101000110000110… |
… | …10101011010110101001 |
3 | 1112111202020102122001002 |
4 | 12110120122223112221 |
5 | 24103221020442101 |
6 | 531245213404345 |
7 | 43240625344310 |
oct | 6243032532651 |
9 | 1474666378032 |
10 | 434201343401 |
11 | 15816437a961 |
12 | 701991996b5 |
13 | 31c3925c747 |
14 | 170305b3277 |
15 | b4642b9d6b |
hex | 65186ab5a9 |
434201343401 has 16 divisors (see below), whose sum is σ = 499061566080. Its totient is φ = 370051355520.
The previous prime is 434201343361. The next prime is 434201343427. The reversal of 434201343401 is 104343102434.
It is a happy number.
It is not a de Polignac number, because 434201343401 - 226 = 434134234537 is a prime.
It is a super-2 number, since 2×4342013434012 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (434201343461) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2120966 + ... + 2316656.
It is an arithmetic number, because the mean of its divisors is an integer number (31191347880).
Almost surely, 2434201343401 is an apocalyptic number.
It is an amenable number.
434201343401 is a deficient number, since it is larger than the sum of its proper divisors (64860222679).
434201343401 is a wasteful number, since it uses less digits than its factorization.
434201343401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 197504.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 434201343401 its reverse (104343102434), we get a palindrome (538544445835).
The spelling of 434201343401 in words is "four hundred thirty-four billion, two hundred one million, three hundred forty-three thousand, four hundred one".
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