4342102012433 has 8 divisors (see below), whose sum is σ = 4360684118400. Its totient is φ = 4323523359568.

The previous prime is 4342102012393. The next prime is 4342102012471. The reversal of 4342102012433 is 3342102012434.

4342102012433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4342102012433 - 2³² = 4337807045137 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4342102012396 and 4342102012405.

It is not an unprimeable number, because it can be changed into a prime (4342102072433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1672910 + ... + 3388632.

It is an arithmetic number, because the mean of its divisors is an integer number (545085514800).

Almost surely, 2^{4342102012433} is an apocalyptic number.

It is an amenable number.

4342102012433 is a deficient number, since it is larger than the sum of its proper divisors (18582105967).

4342102012433 is a wasteful number, since it uses less digits than its factorization.

4342102012433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1726551.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 4342102012433 its reverse (3342102012434), we get a palindrome (7684204024867).

Subtracting from 4342102012433 its reverse (3342102012434), we obtain a palindrome (999999999999).

The spelling of 4342102012433 in words is "four trillion, three hundred forty-two billion, one hundred two million, twelve thousand, four hundred thirty-three".