Base | Representation |
---|---|
bin | 111111001011111001011… |
… | …100101011001000110111 |
3 | 120101002201112222120012111 |
4 | 333023321130223020313 |
5 | 1032120111103344341 |
6 | 13122422323231451 |
7 | 625464223064506 |
oct | 77137134531067 |
9 | 16332645876174 |
10 | 4342102012471 |
11 | 1424525429aa3 |
12 | 5a1641218587 |
13 | 2565c6320752 |
14 | 110231ca083d |
15 | 77e34964681 |
hex | 3f2f972b237 |
4342102012471 has 2 divisors, whose sum is σ = 4342102012472. Its totient is φ = 4342102012470.
The previous prime is 4342102012393. The next prime is 4342102012477. The reversal of 4342102012471 is 1742102012434.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4342102012471 - 233 = 4333512077879 is a prime.
It is a super-3 number, since 3×43421020124713 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4342102012477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2171051006235 + 2171051006236.
It is an arithmetic number, because the mean of its divisors is an integer number (2171051006236).
Almost surely, 24342102012471 is an apocalyptic number.
4342102012471 is a deficient number, since it is larger than the sum of its proper divisors (1).
4342102012471 is an equidigital number, since it uses as much as digits as its factorization.
4342102012471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10752, while the sum is 31.
The spelling of 4342102012471 in words is "four trillion, three hundred forty-two billion, one hundred two million, twelve thousand, four hundred seventy-one".
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