Base | Representation |
---|---|
bin | 111111001011111111100… |
… | …010100110101110010001 |
3 | 120101002222200022210001002 |
4 | 333023333202212232101 |
5 | 1032120313240334140 |
6 | 13122440414151345 |
7 | 625466603655416 |
oct | 77137742465621 |
9 | 16332880283032 |
10 | 4342204230545 |
11 | 14245780a5a45 |
12 | 5a166b4b2555 |
13 | 25661155ca0c |
14 | 1102416ac10d |
15 | 77e3d906415 |
hex | 3f2ff8a6b91 |
4342204230545 has 8 divisors (see below), whose sum is σ = 5213863520640. Its totient is φ = 3471617755120.
The previous prime is 4342204230359. The next prime is 4342204230563. The reversal of 4342204230545 is 5450324022434.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4342204230545 - 210 = 4342204229521 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4342204230499 and 4342204230508.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 268194761 + ... + 268210950.
It is an arithmetic number, because the mean of its divisors is an integer number (651732940080).
Almost surely, 24342204230545 is an apocalyptic number.
It is an amenable number.
4342204230545 is a deficient number, since it is larger than the sum of its proper divisors (871659290095).
4342204230545 is a wasteful number, since it uses less digits than its factorization.
4342204230545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 536407335.
The product of its (nonzero) digits is 460800, while the sum is 38.
Adding to 4342204230545 its reverse (5450324022434), we get a palindrome (9792528252979).
The spelling of 4342204230545 in words is "four trillion, three hundred forty-two billion, two hundred four million, two hundred thirty thousand, five hundred forty-five".
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