Base | Representation |
---|---|
bin | 101000011100010001… |
… | …110011101100101101 |
3 | 11011002022010000002000 |
4 | 220130101303230231 |
5 | 1202413032300323 |
6 | 31540533122513 |
7 | 3065042534001 |
oct | 503421635455 |
9 | 134068100060 |
10 | 43424103213 |
11 | 17463857507 |
12 | 84ba789439 |
13 | 413059733a |
14 | 215d250701 |
15 | 11e2400e43 |
hex | a1c473b2d |
43424103213 has 16 divisors (see below), whose sum is σ = 66407232000. Its totient is φ = 28015549920.
The previous prime is 43424103211. The next prime is 43424103253. The reversal of 43424103213 is 31230142434.
43424103213 is a `hidden beast` number, since 4 + 34 + 2 + 410 + 3 + 213 = 666.
43424103213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 43424103213 - 21 = 43424103211 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43424103211) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25939488 + ... + 25941161.
It is an arithmetic number, because the mean of its divisors is an integer number (4150452000).
Almost surely, 243424103213 is an apocalyptic number.
It is an amenable number.
43424103213 is a deficient number, since it is larger than the sum of its proper divisors (22983128787).
43424103213 is a wasteful number, since it uses less digits than its factorization.
43424103213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51880689 (or 51880683 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 43424103213 its reverse (31230142434), we get a palindrome (74654245647).
The spelling of 43424103213 in words is "forty-three billion, four hundred twenty-four million, one hundred three thousand, two hundred thirteen".
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