Base | Representation |
---|---|
bin | 101000011100010011… |
… | …110111010110000011 |
3 | 11011002100010101202012 |
4 | 220130103313112003 |
5 | 1202413202024220 |
6 | 31540552443135 |
7 | 3065050241036 |
oct | 503423672603 |
9 | 134070111665 |
10 | 43424642435 |
11 | 17464095649 |
12 | 84ba9a94ab |
13 | 41307258c5 |
14 | 215d35101d |
15 | 11e24aaac5 |
hex | a1c4f7583 |
43424642435 has 16 divisors (see below), whose sum is σ = 52601551200. Its totient is φ = 34411896576.
The previous prime is 43424642431. The next prime is 43424642449. The reversal of 43424642435 is 53424642434.
It is a happy number.
43424642435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 43424642435 - 22 = 43424642431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 43424642392 and 43424642401.
It is not an unprimeable number, because it can be changed into a prime (43424642431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2682596 + ... + 2698734.
It is an arithmetic number, because the mean of its divisors is an integer number (3287596950).
Almost surely, 243424642435 is an apocalyptic number.
43424642435 is a deficient number, since it is larger than the sum of its proper divisors (9176908765).
43424642435 is a wasteful number, since it uses less digits than its factorization.
43424642435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21190.
The product of its digits is 1105920, while the sum is 41.
Subtracting 43424642435 from its reverse (53424642434), we obtain a palindrome (9999999999).
The spelling of 43424642435 in words is "forty-three billion, four hundred twenty-four million, six hundred forty-two thousand, four hundred thirty-five".
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