Base | Representation |
---|---|
bin | 10011110000010001100011… |
… | …01100111110001100110001 |
3 | 12200210211120120021121012201 |
4 | 21320020301230332030301 |
5 | 21143210343033320213 |
6 | 232220042135423201 |
7 | 12102305665003162 |
oct | 1170106154761461 |
9 | 180724516247181 |
10 | 43440133104433 |
11 | 1292894772354a |
12 | 4a56ba4824b01 |
13 | 1b3150524ca70 |
14 | aa27296ad769 |
15 | 504e9e3846dd |
hex | 278231b3e331 |
43440133104433 has 4 divisors (see below), whose sum is σ = 46781681804788. Its totient is φ = 40098584404080.
The previous prime is 43440133104377. The next prime is 43440133104451. The reversal of 43440133104433 is 33440133104434.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 14775159759409 + 28664973345024 = 3843847^2 + 5353968^2 .
It is a cyclic number.
It is not a de Polignac number, because 43440133104433 - 29 = 43440133103921 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 43440133104392 and 43440133104401.
It is not an unprimeable number, because it can be changed into a prime (43440133144433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1670774350158 + ... + 1670774350183.
It is an arithmetic number, because the mean of its divisors is an integer number (11695420451197).
Almost surely, 243440133104433 is an apocalyptic number.
It is an amenable number.
43440133104433 is a deficient number, since it is larger than the sum of its proper divisors (3341548700355).
43440133104433 is a wasteful number, since it uses less digits than its factorization.
43440133104433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3341548700354.
The product of its (nonzero) digits is 248832, while the sum is 37.
Adding to 43440133104433 its reverse (33440133104434), we get a palindrome (76880266208867).
Subtracting from 43440133104433 its reverse (33440133104434), we obtain a palindrome (9999999999999).
The spelling of 43440133104433 in words is "forty-three trillion, four hundred forty billion, one hundred thirty-three million, one hundred four thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •