Base | Representation |
---|---|
bin | 10011110000010001100011… |
… | …01100111110001101000011 |
3 | 12200210211120120021121020101 |
4 | 21320020301230332031003 |
5 | 21143210343033320301 |
6 | 232220042135423231 |
7 | 12102305665003216 |
oct | 1170106154761503 |
9 | 180724516247211 |
10 | 43440133104451 |
11 | 12928947723566 |
12 | 4a56ba4824b17 |
13 | 1b3150524ca85 |
14 | aa27296ad77d |
15 | 504e9e384701 |
hex | 278231b3e343 |
43440133104451 has 2 divisors, whose sum is σ = 43440133104452. Its totient is φ = 43440133104450.
The previous prime is 43440133104377. The next prime is 43440133104479. The reversal of 43440133104451 is 15440133104434.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43440133104451 - 225 = 43440099550019 is a prime.
It is a super-2 number, since 2×434401331044512 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 43440133104451.
It is not a weakly prime, because it can be changed into another prime (43440133104481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21720066552225 + 21720066552226.
It is an arithmetic number, because the mean of its divisors is an integer number (21720066552226).
Almost surely, 243440133104451 is an apocalyptic number.
43440133104451 is a deficient number, since it is larger than the sum of its proper divisors (1).
43440133104451 is an equidigital number, since it uses as much as digits as its factorization.
43440133104451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 138240, while the sum is 37.
Adding to 43440133104451 its reverse (15440133104434), we get a palindrome (58880266208885).
The spelling of 43440133104451 in words is "forty-three trillion, four hundred forty billion, one hundred thirty-three million, one hundred four thousand, four hundred fifty-one".
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