Base | Representation |
---|---|
bin | 1100101001001101011… |
… | …10000011010100100011 |
3 | 1112112100221221212011220 |
4 | 12110212232003110203 |
5 | 24104213433201311 |
6 | 531325104510123 |
7 | 43246601102040 |
oct | 6244656032443 |
9 | 1475327855156 |
10 | 434441303331 |
11 | 158277876352 |
12 | 7024561b343 |
13 | 31c76b98279 |
14 | 170543d81c7 |
15 | b47a3b9206 |
hex | 6526b83523 |
434441303331 has 16 divisors (see below), whose sum is σ = 668830600704. Its totient is φ = 245692871424.
The previous prime is 434441303297. The next prime is 434441303333. The reversal of 434441303331 is 133303144434.
It is not a de Polignac number, because 434441303331 - 213 = 434441295139 is a prime.
It is a super-2 number, since 2×4344413033312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 434441303292 and 434441303301.
It is not an unprimeable number, because it can be changed into a prime (434441303333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 106635495 + ... + 106639568.
It is an arithmetic number, because the mean of its divisors is an integer number (41801912544).
Almost surely, 2434441303331 is an apocalyptic number.
434441303331 is a deficient number, since it is larger than the sum of its proper divisors (234389297373).
434441303331 is a wasteful number, since it uses less digits than its factorization.
434441303331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 213275170.
The product of its (nonzero) digits is 62208, while the sum is 33.
Adding to 434441303331 its reverse (133303144434), we get a palindrome (567744447765).
The spelling of 434441303331 in words is "four hundred thirty-four billion, four hundred forty-one million, three hundred three thousand, three hundred thirty-one".
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