Base | Representation |
---|---|
bin | 111111001110000100010… |
… | …010101000001100110111 |
3 | 120101022201220011022122222 |
4 | 333032010102220030313 |
5 | 1032134343420141043 |
6 | 13123445414312555 |
7 | 625606026464033 |
oct | 77160422501467 |
9 | 16338656138588 |
10 | 4344431412023 |
11 | 142551030039a |
12 | 5a1b9135875b |
13 | 2568a7aba491 |
14 | 1103b33c31c3 |
15 | 7801e1e1d68 |
hex | 3f3844a8337 |
4344431412023 has 4 divisors (see below), whose sum is σ = 4347966345240. Its totient is φ = 4340896478808.
The previous prime is 4344431412019. The next prime is 4344431412047. The reversal of 4344431412023 is 3202141344434.
4344431412023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4344431412023 - 22 = 4344431412019 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4344431412523) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1767464765 + ... + 1767467222.
It is an arithmetic number, because the mean of its divisors is an integer number (1086991586310).
Almost surely, 24344431412023 is an apocalyptic number.
4344431412023 is a deficient number, since it is larger than the sum of its proper divisors (3534933217).
4344431412023 is a wasteful number, since it uses less digits than its factorization.
4344431412023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3534933216.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 4344431412023 its reverse (3202141344434), we get a palindrome (7546572756457).
The spelling of 4344431412023 in words is "four trillion, three hundred forty-four billion, four hundred thirty-one million, four hundred twelve thousand, twenty-three".
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