Base | Representation |
---|---|
bin | 111111010111010111001… |
… | …111111000001000000111 |
3 | 120102021111112112100112020 |
4 | 333113113033320020013 |
5 | 1032320314230244333 |
6 | 13132220105254223 |
7 | 626411262642216 |
oct | 77272717701007 |
9 | 16367445470466 |
10 | 4354413134343 |
11 | 1429772771088 |
12 | 5a3ab8194373 |
13 | 257808a7844c |
14 | 110a7cd4907d |
15 | 7840568e3b3 |
hex | 3f5d73f8207 |
4354413134343 has 16 divisors (see below), whose sum is σ = 6231617834976. Its totient is φ = 2694753653760.
The previous prime is 4354413134333. The next prime is 4354413134417. The reversal of 4354413134343 is 3434313144534.
It is not a de Polignac number, because 4354413134343 - 216 = 4354413068807 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4354413134295 and 4354413134304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4354413134333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 584795248 + ... + 584802693.
It is an arithmetic number, because the mean of its divisors is an integer number (389476114686).
Almost surely, 24354413134343 is an apocalyptic number.
4354413134343 is a deficient number, since it is larger than the sum of its proper divisors (1877204700633).
4354413134343 is a wasteful number, since it uses less digits than its factorization.
4354413134343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1169598034.
The product of its digits is 1244160, while the sum is 42.
Adding to 4354413134343 its reverse (3434313144534), we get a palindrome (7788726278877).
The spelling of 4354413134343 in words is "four trillion, three hundred fifty-four billion, four hundred thirteen million, one hundred thirty-four thousand, three hundred forty-three".
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