43950613091045 has 4 divisors (see below), whose sum is σ = 52740735709260. Its totient is φ = 35160490472832.

The previous prime is 43950613091029. The next prime is 43950613091051. The reversal of 43950613091045 is 54019031605934.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 26438179225249 + 17512433865796 = 5141807^2 + 4184786^2 .

It is a cyclic number.

It is not a de Polignac number, because 43950613091045 - 2⁴ = 43950613091029 is a prime.

It is a super-2 number, since 2×43950613091045² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43950613090984 and 43950613091002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4395061309100 + ... + 4395061309109.

It is an arithmetic number, because the mean of its divisors is an integer number (13185183927315).

Almost surely, 2^{43950613091045} is an apocalyptic number.

It is an amenable number.

43950613091045 is a deficient number, since it is larger than the sum of its proper divisors (8790122618215).

43950613091045 is an equidigital number, since it uses as much as digits as its factorization.

43950613091045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8790122618214.

The product of its (nonzero) digits is 1749600, while the sum is 50.

Adding to 43950613091045 its reverse (54019031605934), we get a palindrome (97969644696979).

The spelling of 43950613091045 in words is "forty-three trillion, nine hundred fifty billion, six hundred thirteen million, ninety-one thousand, forty-five".