Base | Representation |
---|---|
bin | 11010001110001… |
… | …000111010001001 |
3 | 1010122202221201121 |
4 | 122032020322021 |
5 | 1400104222441 |
6 | 111352515241 |
7 | 13621131313 |
oct | 3216107211 |
9 | 1118687647 |
10 | 439914121 |
11 | 206357a99 |
12 | 1033abb21 |
13 | 701a801a |
14 | 425d47b3 |
15 | 28949dd1 |
hex | 1a388e89 |
439914121 has 4 divisors (see below), whose sum is σ = 439972992. Its totient is φ = 439855252.
The previous prime is 439914103. The next prime is 439914131. The reversal of 439914121 is 121419934.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 439914121 - 27 = 439913993 is a prime.
It is a super-3 number, since 3×4399141213 (a number of 27 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (439914131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16261 + ... + 33826.
It is an arithmetic number, because the mean of its divisors is an integer number (109993248).
Almost surely, 2439914121 is an apocalyptic number.
It is an amenable number.
439914121 is a deficient number, since it is larger than the sum of its proper divisors (58871).
439914121 is an equidigital number, since it uses as much as digits as its factorization.
439914121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58870.
The product of its digits is 7776, while the sum is 34.
The square root of 439914121 is about 20974.1298031647. The cubic root of 439914121 is about 760.5410050303.
The spelling of 439914121 in words is "four hundred thirty-nine million, nine hundred fourteen thousand, one hundred twenty-one".
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