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4400113103111 = 11400010282101
BaseRepresentation
bin100000000000111101100…
…1011011011000100000111
3120120122110110002022020002
41000001323023123010013
51034042412423244421
613205214542231515
7632616622161605
oct100017313330407
916518413068202
104400113103111
111447094155010
125b0930b8559b
1325bc0c9b769b
14112d76544875
15796cc795b0b
hex4007b2db107

4400113103111 has 4 divisors (see below), whose sum is σ = 4800123385224. Its totient is φ = 4000102821000.

The previous prime is 4400113103101. The next prime is 4400113103137. The reversal of 4400113103111 is 1113013110044.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 4400113103111 - 218 = 4400112840967 is a prime.

It is a super-2 number, since 2×44001131031112 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4400113103101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200005141040 + ... + 200005141061.

It is an arithmetic number, because the mean of its divisors is an integer number (1200030846306).

Almost surely, 24400113103111 is an apocalyptic number.

4400113103111 is a deficient number, since it is larger than the sum of its proper divisors (400010282113).

4400113103111 is a wasteful number, since it uses less digits than its factorization.

4400113103111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 400010282112.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 4400113103111 its reverse (1113013110044), we get a palindrome (5513126213155).

The spelling of 4400113103111 in words is "four trillion, four hundred billion, one hundred thirteen million, one hundred three thousand, one hundred eleven".

Divisors: 1 11 400010282101 4400113103111