Base | Representation |
---|---|
bin | 100000000001011100000… |
… | …0011000001101011001111 |
3 | 120120202002121200002122211 |
4 | 1000002320003001223033 |
5 | 1034102010340442033 |
6 | 13205504142251251 |
7 | 632654132255452 |
oct | 100027003015317 |
9 | 16522077602584 |
10 | 4401134312143 |
11 | 1447568644518 |
12 | 5b0b76b86b27 |
13 | 25c04343c39a |
14 | 113032013499 |
15 | 7973c2662cd |
hex | 400b80c1acf |
4401134312143 has 4 divisors (see below), whose sum is σ = 4401180782128. Its totient is φ = 4401087842160.
The previous prime is 4401134312131. The next prime is 4401134312249. The reversal of 4401134312143 is 3412134311044.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4401134312143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4401134319143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23092638 + ... + 23282443.
It is an arithmetic number, because the mean of its divisors is an integer number (1100295195532).
Almost surely, 24401134312143 is an apocalyptic number.
4401134312143 is a deficient number, since it is larger than the sum of its proper divisors (46469985).
4401134312143 is an equidigital number, since it uses as much as digits as its factorization.
4401134312143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46469984.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 4401134312143 its reverse (3412134311044), we get a palindrome (7813268623187).
The spelling of 4401134312143 in words is "four trillion, four hundred one billion, one hundred thirty-four million, three hundred twelve thousand, one hundred forty-three".
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