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44031121513 = 411073929793
BaseRepresentation
bin101001000000011101…
…011001100001101001
311012122121022201122021
4221000131121201221
51210133431342023
632121055424441
73116063233441
oct510035314151
9135577281567
1044031121513
1117745469325
128649b25121
1341c927c572
1421b9b03121
15122a85835d
hexa40759869

44031121513 has 4 divisors (see below), whose sum is σ = 45105051348. Its totient is φ = 42957191680.

The previous prime is 44031121489. The next prime is 44031121597. The reversal of 44031121513 is 31512113044.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 14489418384 + 29541703129 = 120372^2 + 171877^2 .

It is a cyclic number.

It is not a de Polignac number, because 44031121513 - 217 = 44030990441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (44031121213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 536964856 + ... + 536964937.

It is an arithmetic number, because the mean of its divisors is an integer number (11276262837).

Almost surely, 244031121513 is an apocalyptic number.

It is an amenable number.

44031121513 is a deficient number, since it is larger than the sum of its proper divisors (1073929835).

44031121513 is a wasteful number, since it uses less digits than its factorization.

44031121513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1073929834.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 44031121513 its reverse (31512113044), we get a palindrome (75543234557).

The spelling of 44031121513 in words is "forty-four billion, thirty-one million, one hundred twenty-one thousand, five hundred thirteen".

Divisors: 1 41 1073929793 44031121513