440313431324341 has 4 divisors (see below), whose sum is σ = 440318892385900. Its totient is φ = 440307970262784.

The previous prime is 440313431324297. The next prime is 440313431324359. The reversal of 440313431324341 is 143423134313044.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 285303212228241 + 155010219096100 = 16890921^2 + 12450310^2 .

It is a cyclic number.

It is not a de Polignac number, because 440313431324341 - 2³¹ = 440311283840693 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 440313431324294 and 440313431324303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (440313431324381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2730409836 + ... + 2730571093.

It is an arithmetic number, because the mean of its divisors is an integer number (110079723096475).

Almost surely, 2^{440313431324341} is an apocalyptic number.

It is an amenable number.

440313431324341 is a deficient number, since it is larger than the sum of its proper divisors (5461061559).

440313431324341 is an equidigital number, since it uses as much as digits as its factorization.

440313431324341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5461061558.

The product of its (nonzero) digits is 497664, while the sum is 40.

Adding to 440313431324341 its reverse (143423134313044), we get a palindrome (583736565637385).

The spelling of 440313431324341 in words is "four hundred forty trillion, three hundred thirteen billion, four hundred thirty-one million, three hundred twenty-four thousand, three hundred forty-one".