4404012113 has 4 divisors (see below), whose sum is σ = 4404151920. Its totient is φ = 4403872308.

The previous prime is 4404012083. The next prime is 4404012133. The reversal of 4404012113 is 3112104044.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 4404012113 - 2⁶ = 4404012049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (4404012133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2006 + ... + 93872.

It is an arithmetic number, because the mean of its divisors is an integer number (1101037980).

Almost surely, 2^4404012113 is an apocalyptic number.

It is an amenable number.

4404012113 is a deficient number, since it is larger than the sum of its proper divisors (139807).

4404012113 is an equidigital number, since it uses as much as digits as its factorization.

4404012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 139806.

The product of its (nonzero) digits is 384, while the sum is 20.

The square root of 4404012113 is about 66362.7313557843. The cubic root of 4404012113 is about 1639.1404519416.

Adding to 4404012113 its reverse (3112104044), we get a palindrome (7516116157).

The spelling of 4404012113 in words is "four billion, four hundred four million, twelve thousand, one hundred thirteen".