Base | Representation |
---|---|
bin | 1000001100111111… |
… | …11110010001100101 |
3 | 102100220220222220111 |
4 | 10012133332101211 |
5 | 33004411342013 |
6 | 2005001133021 |
7 | 214064325343 |
oct | 40637762145 |
9 | 12326828814 |
10 | 4404012133 |
11 | 195aa4a554 |
12 | a2aa8a171 |
13 | 552539251 |
14 | 2dac80993 |
15 | 1ab97c73d |
hex | 1067fe465 |
4404012133 has 2 divisors, whose sum is σ = 4404012134. Its totient is φ = 4404012132.
The previous prime is 4404012083. The next prime is 4404012149. The reversal of 4404012133 is 3312104044.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4382175204 + 21836929 = 66198^2 + 4673^2 .
It is a cyclic number.
It is not a de Polignac number, because 4404012133 - 213 = 4404003941 is a prime.
It is a super-2 number, since 2×44040121332 = 38790645735222419378, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4404012233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2202006066 + 2202006067.
It is an arithmetic number, because the mean of its divisors is an integer number (2202006067).
Almost surely, 24404012133 is an apocalyptic number.
It is an amenable number.
4404012133 is a deficient number, since it is larger than the sum of its proper divisors (1).
4404012133 is an equidigital number, since it uses as much as digits as its factorization.
4404012133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 22.
The square root of 4404012133 is about 66362.7315064713. The cubic root of 4404012133 is about 1639.1404544229.
Adding to 4404012133 its reverse (3312104044), we get a palindrome (7716116177).
The spelling of 4404012133 in words is "four billion, four hundred four million, twelve thousand, one hundred thirty-three".
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