44040490231 has 4 divisors (see below), whose sum is σ = 44041317832. Its totient is φ = 44039662632.

The previous prime is 44040490217. The next prime is 44040490243. The reversal of 44040490231 is 13209404044.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 44040490231 - 2⁵ = 44040490199 is a prime.

It is a super-2 number, since 2×44040490231² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 44040490193 and 44040490202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (44040490271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 328056 + ... + 442381.

It is an arithmetic number, because the mean of its divisors is an integer number (11010329458).

Almost surely, 2^44040490231 is an apocalyptic number.

44040490231 is a deficient number, since it is larger than the sum of its proper divisors (827601).

44040490231 is an equidigital number, since it uses as much as digits as its factorization.

44040490231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 827600.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 44040490231 its reverse (13209404044), we get a palindrome (57249894275).

The spelling of 44040490231 in words is "forty-four billion, forty million, four hundred ninety thousand, two hundred thirty-one".