4404052113135 has 8 divisors (see below), whose sum is σ = 7046483381040. Its totient is φ = 2348827793664.

The previous prime is 4404052113133. The next prime is 4404052113161. The reversal of 4404052113135 is 5313112504044.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 4404052113135 - 2¹ = 4404052113133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4404052113096 and 4404052113105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4404052113133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 146801737090 + ... + 146801737119.

It is an arithmetic number, because the mean of its divisors is an integer number (880810422630).

Almost surely, 2^{4404052113135} is an apocalyptic number.

4404052113135 is a deficient number, since it is larger than the sum of its proper divisors (2642431267905).

4404052113135 is a wasteful number, since it uses less digits than its factorization.

4404052113135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 293603474217.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 4404052113135 its reverse (5313112504044), we get a palindrome (9717164617179).

The spelling of 4404052113135 in words is "four trillion, four hundred four billion, fifty-two million, one hundred thirteen thousand, one hundred thirty-five".