Base | Representation |
---|---|
bin | 100000000011010000110… |
… | …0101011001011001110011 |
3 | 120121010012200021021100221 |
4 | 1000012201211121121303 |
5 | 1034133021404213210 |
6 | 13211353024553511 |
7 | 633153206500603 |
oct | 100064145313163 |
9 | 16533180237327 |
10 | 4405052413555 |
11 | 1449199280062 |
12 | 5b188b182897 |
13 | 25c5190b74a1 |
14 | 1132c4528c03 |
15 | 798bb2101da |
hex | 401a1959673 |
4405052413555 has 24 divisors (see below), whose sum is σ = 5461504749360. Its totient is φ = 3410507903040.
The previous prime is 4405052413537. The next prime is 4405052413589. The reversal of 4405052413555 is 5553142505044.
It is not a de Polignac number, because 4405052413555 - 27 = 4405052413427 is a prime.
It is a super-3 number, since 3×44050524135553 (a number of 39 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1177981 + ... + 3193390.
It is an arithmetic number, because the mean of its divisors is an integer number (227562697890).
Almost surely, 24405052413555 is an apocalyptic number.
4405052413555 is a deficient number, since it is larger than the sum of its proper divisors (1056452335805).
4405052413555 is a wasteful number, since it uses less digits than its factorization.
4405052413555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4371571 (or 4371528 counting only the distinct ones).
The product of its (nonzero) digits is 1200000, while the sum is 43.
Adding to 4405052413555 its reverse (5553142505044), we get a palindrome (9958194918599).
The spelling of 4405052413555 in words is "four trillion, four hundred five billion, fifty-two million, four hundred thirteen thousand, five hundred fifty-five".
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