4411412140433 has 4 divisors (see below), whose sum is σ = 4411851577920. Its totient is φ = 4410972702948.

The previous prime is 4411412140381. The next prime is 4411412140453. The reversal of 4411412140433 is 3340412141144.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4411412140433 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4411412140433.

It is not an unprimeable number, because it can be changed into a prime (4411412140453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219703685 + ... + 219723762.

It is an arithmetic number, because the mean of its divisors is an integer number (1102962894480).

Almost surely, 2^{4411412140433} is an apocalyptic number.

It is an amenable number.

4411412140433 is a deficient number, since it is larger than the sum of its proper divisors (439437487).

4411412140433 is a wasteful number, since it uses less digits than its factorization.

4411412140433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 439437486.

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 4411412140433 its reverse (3340412141144), we get a palindrome (7751824281577).

The spelling of 4411412140433 in words is "four trillion, four hundred eleven billion, four hundred twelve million, one hundred forty thousand, four hundred thirty-three".