Base | Representation |
---|---|
bin | 110010001010111000010101… |
… | …0111100110100001110011011 |
3 | 2010212111212111011202200200011 |
4 | 1210111300222330310032123 |
5 | 430320224420200040120 |
6 | 4202322233002222351 |
7 | 161644605615241210 |
oct | 14425605274641633 |
9 | 2125455434680604 |
10 | 441300020315035 |
11 | 118680318888942 |
12 | 415b2a97ab49b7 |
13 | 15c3154b1a357b |
14 | 7ad906bc79b07 |
15 | 360435d934c5a |
hex | 1915c2af3439b |
441300020315035 has 48 divisors (see below), whose sum is σ = 620347244306688. Its totient is φ = 295218198961920.
The previous prime is 441300020315027. The next prime is 441300020315081. The reversal of 441300020315035 is 530513020003144.
It is not a de Polignac number, because 441300020315035 - 23 = 441300020315027 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 441300020314988 and 441300020315006.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4355327884 + ... + 4355429206.
It is an arithmetic number, because the mean of its divisors is an integer number (12923900923056).
Almost surely, 2441300020315035 is an apocalyptic number.
441300020315035 is a deficient number, since it is larger than the sum of its proper divisors (179047223991653).
441300020315035 is a wasteful number, since it uses less digits than its factorization.
441300020315035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 175444 (or 175403 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 441300020315035 its reverse (530513020003144), we get a palindrome (971813040318179).
The spelling of 441300020315035 in words is "four hundred forty-one trillion, three hundred billion, twenty million, three hundred fifteen thousand, thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •