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44130003301 = 95114639891
BaseRepresentation
bin101001000110010110…
…100110100101100101
311012220111101102221201
4221012112212211211
51210334240101201
632134551042501
73121403560516
oct510626464545
9135814342851
1044130003301
111779626670a
128677070431
1342138c10b7
1421c8cc2a0d
15123438b801
hexa465a6965

44130003301 has 4 divisors (see below), whose sum is σ = 44134652704. Its totient is φ = 44125353900.

The previous prime is 44130003287. The next prime is 44130003329. The reversal of 44130003301 is 10330003144.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 44130003301 - 221 = 44127906149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (44130003361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2310435 + ... + 2329456.

It is an arithmetic number, because the mean of its divisors is an integer number (11033663176).

Almost surely, 244130003301 is an apocalyptic number.

It is an amenable number.

44130003301 is a deficient number, since it is larger than the sum of its proper divisors (4649403).

44130003301 is an equidigital number, since it uses as much as digits as its factorization.

44130003301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4649402.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 44130003301 its reverse (10330003144), we get a palindrome (54460006445).

The spelling of 44130003301 in words is "forty-four billion, one hundred thirty million, three thousand, three hundred one".

Divisors: 1 9511 4639891 44130003301