Base | Representation |
---|---|
bin | 100000000111000101000… |
… | …1100111101011011010111 |
3 | 120121220100222121011122011 |
4 | 1000032022030331123113 |
5 | 1034301314004104020 |
6 | 13215230305045051 |
7 | 633563310420421 |
oct | 100161214753327 |
9 | 16556328534564 |
10 | 4413250066135 |
11 | 1451715677849 |
12 | 5b3398626787 |
13 | 2602245722a1 |
14 | 113861163811 |
15 | 79beac4e35a |
hex | 4038a33d6d7 |
4413250066135 has 4 divisors (see below), whose sum is σ = 5295900079368. Its totient is φ = 3530600052904.
The previous prime is 4413250066123. The next prime is 4413250066217. The reversal of 4413250066135 is 5316600523144.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4413250066135 - 25 = 4413250066103 is a prime.
It is a super-2 number, since 2×44132500661352 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 441325006609 + ... + 441325006618.
It is an arithmetic number, because the mean of its divisors is an integer number (1323975019842).
Almost surely, 24413250066135 is an apocalyptic number.
4413250066135 is a deficient number, since it is larger than the sum of its proper divisors (882650013233).
4413250066135 is an equidigital number, since it uses as much as digits as its factorization.
4413250066135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 882650013232.
The product of its (nonzero) digits is 259200, while the sum is 40.
Adding to 4413250066135 its reverse (5316600523144), we get a palindrome (9729850589279).
The spelling of 4413250066135 in words is "four trillion, four hundred thirteen billion, two hundred fifty million, sixty-six thousand, one hundred thirty-five".
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