Base | Representation |
---|---|
bin | 100000000111000111001… |
… | …1101010010010110111010 |
3 | 120121220112221221002210110 |
4 | 1000032032131102112322 |
5 | 1034301440243030114 |
6 | 13215241335125150 |
7 | 633565135260342 |
oct | 100161635222672 |
9 | 16556487832713 |
10 | 4413321455034 |
11 | 14517519a7338 |
12 | 5b33b85137b6 |
13 | 2602362a903b |
14 | 11386a827d22 |
15 | 79c02151759 |
hex | 4038e7525ba |
4413321455034 has 16 divisors (see below), whose sum is σ = 8827602125472. Its totient is φ = 1470947282448.
The previous prime is 4413321454999. The next prime is 4413321455047. The reversal of 4413321455034 is 4305541233144.
It is a super-3 number, since 3×44133214550343 (a number of 39 digits) contains 333 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 4413321454983 and 4413321455001.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39907489 + ... + 40017924.
It is an arithmetic number, because the mean of its divisors is an integer number (551725132842).
Almost surely, 24413321455034 is an apocalyptic number.
4413321455034 is an abundant number, since it is smaller than the sum of its proper divisors (4414280670438).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4413321455034 is a wasteful number, since it uses less digits than its factorization.
4413321455034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79934621.
The product of its (nonzero) digits is 345600, while the sum is 39.
Adding to 4413321455034 its reverse (4305541233144), we get a palindrome (8718862688178).
The spelling of 4413321455034 in words is "four trillion, four hundred thirteen billion, three hundred twenty-one million, four hundred fifty-five thousand, thirty-four".
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