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44204130035 = 5134714469437
BaseRepresentation
bin101001001010110001…
…010111111011110011
311020002122212110201022
4221022301113323303
51211012224130120
632150155530055
73123263622452
oct511261277363
9136078773638
1044204130035
111782409617a
128697a5992b
134226076080
1421d4a9ab99
15123ab30025
hexa4ac57ef3

44204130035 has 16 divisors (see below), whose sum is σ = 58340774016. Its totient is φ = 31948514688.

The previous prime is 44204130007. The next prime is 44204130071. The reversal of 44204130035 is 53003140244.

It is a cyclic number.

It is not a de Polignac number, because 44204130035 - 212 = 44204125939 is a prime.

It is a super-3 number, since 3×442041300353 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 44204129986 and 44204130013.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7231664 + ... + 7237773.

It is an arithmetic number, because the mean of its divisors is an integer number (3646298376).

Almost surely, 244204130035 is an apocalyptic number.

44204130035 is a deficient number, since it is larger than the sum of its proper divisors (14136643981).

44204130035 is a wasteful number, since it uses less digits than its factorization.

44204130035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14469502.

The product of its (nonzero) digits is 5760, while the sum is 26.

Adding to 44204130035 its reverse (53003140244), we get a palindrome (97207270279).

The spelling of 44204130035 in words is "forty-four billion, two hundred four million, one hundred thirty thousand, thirty-five".

Divisors: 1 5 13 47 65 235 611 3055 14469437 72347185 188102681 680063539 940513405 3400317695 8840826007 44204130035