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44230002013 = 44399841991
BaseRepresentation
bin101001001100010100…
…000100010101011101
311020011110112220101201
4221030110010111131
51211040340031023
632152522235501
73124026546121
oct511424042535
9136143486351
1044230002013
111783775717a
1286a4655b91
13422b534132
1421d82b3581
15123d040bad
hexa4c50455d

44230002013 has 4 divisors (see below), whose sum is σ = 44329844448. Its totient is φ = 44130159580.

The previous prime is 44230001987. The next prime is 44230002023. The reversal of 44230002013 is 31020003244.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-44230002013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (44230002023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49920553 + ... + 49921438.

It is an arithmetic number, because the mean of its divisors is an integer number (11082461112).

Almost surely, 244230002013 is an apocalyptic number.

It is an amenable number.

44230002013 is a deficient number, since it is larger than the sum of its proper divisors (99842435).

44230002013 is an equidigital number, since it uses as much as digits as its factorization.

44230002013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 99842434.

The product of its (nonzero) digits is 576, while the sum is 19.

Adding to 44230002013 its reverse (31020003244), we get a palindrome (75250005257).

The spelling of 44230002013 in words is "forty-four billion, two hundred thirty million, two thousand, thirteen".

Divisors: 1 443 99841991 44230002013