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4431000231313 = 23994718466579
BaseRepresentation
bin100000001111010110000…
…1100011101110110010001
3120200121012000122222201021
41000132230030131312101
51040044142024400223
613231323504435441
7635062213346215
oct100365414356621
916617160588637
104431000231313
1114591a4129647
125b6911018b81
13261ac2aba3c6
14114666718945
157a3d920765d
hex407ac31dd91

4431000231313 has 4 divisors (see below), whose sum is σ = 4431018937840. Its totient is φ = 4430981524788.

The previous prime is 4431000231277. The next prime is 4431000231389. The reversal of 4431000231313 is 3131320001344.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4431000231313 - 225 = 4430966676881 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4431000631313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8993343 + ... + 9473236.

It is an arithmetic number, because the mean of its divisors is an integer number (1107754734460).

Almost surely, 24431000231313 is an apocalyptic number.

It is an amenable number.

4431000231313 is a deficient number, since it is larger than the sum of its proper divisors (18706527).

4431000231313 is a wasteful number, since it uses less digits than its factorization.

4431000231313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18706526.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 4431000231313 its reverse (3131320001344), we get a palindrome (7562320232657).

The spelling of 4431000231313 in words is "four trillion, four hundred thirty-one billion, two hundred thirty-one thousand, three hundred thirteen".

Divisors: 1 239947 18466579 4431000231313