44312064133 has 4 divisors (see below), whose sum is σ = 44318185920. Its totient is φ = 44305942348.

The previous prime is 44312064107. The next prime is 44312064151. The reversal of 44312064133 is 33146021344.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-44312064133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 44312064095 and 44312064104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (44312064103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3050023 + ... + 3064516.

It is an arithmetic number, because the mean of its divisors is an integer number (11079546480).

Almost surely, 2^44312064133 is an apocalyptic number.

It is an amenable number.

44312064133 is a deficient number, since it is larger than the sum of its proper divisors (6121787).

44312064133 is an equidigital number, since it uses as much as digits as its factorization.

44312064133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6121786.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 44312064133 its reverse (33146021344), we get a palindrome (77458085477).

The spelling of 44312064133 in words is "forty-four billion, three hundred twelve million, sixty-four thousand, one hundred thirty-three".