Base | Representation |
---|---|
bin | 110010011000001000011100… |
… | …1001000001011111000011001 |
3 | 2011002221222120222112221020220 |
4 | 1210300100321020023320121 |
5 | 431040044433010410131 |
6 | 4210235043123510253 |
7 | 162223313334615666 |
oct | 14460207110137031 |
9 | 2132858528487226 |
10 | 443121324310041 |
11 | 119212775473273 |
12 | 41847a6ab28389 |
13 | 16034213cc9880 |
14 | 7b5d287bb0a6d |
15 | 3636908937e96 |
hex | 193043920be19 |
443121324310041 has 16 divisors (see below), whose sum is σ = 636632832099264. Its totient is φ = 272537449130304.
The previous prime is 443121324310033. The next prime is 443121324310081. The reversal of 443121324310041 is 140013423121344.
It is a happy number.
It is not a de Polignac number, because 443121324310041 - 23 = 443121324310033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 443121324309984 and 443121324310011.
It is not an unprimeable number, because it can be changed into a prime (443121324310081) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3179025226 + ... + 3179164611.
It is an arithmetic number, because the mean of its divisors is an integer number (39789552006204).
Almost surely, 2443121324310041 is an apocalyptic number.
It is an amenable number.
443121324310041 is a deficient number, since it is larger than the sum of its proper divisors (193511507789223).
443121324310041 is a wasteful number, since it uses less digits than its factorization.
443121324310041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6358191640.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 443121324310041 its reverse (140013423121344), we get a palindrome (583134747431385).
The spelling of 443121324310041 in words is "four hundred forty-three trillion, one hundred twenty-one billion, three hundred twenty-four million, three hundred ten thousand, forty-one".
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