Base | Representation |
---|---|
bin | 100000001111011111011… |
… | …0111001010011110011001 |
3 | 120200121222211222022122120 |
4 | 1000132332313022132121 |
5 | 1040100312213222131 |
6 | 13231414533211453 |
7 | 635103035352333 |
oct | 100367667123631 |
9 | 16617884868576 |
10 | 4431313414041 |
11 | 1459344997448 |
12 | 5b6999a90b89 |
13 | 261b42952627 |
14 | 114696160453 |
15 | 7a40696c496 |
hex | 407bedca799 |
4431313414041 has 32 divisors (see below), whose sum is σ = 6156984960000. Its totient is φ = 2831425412928.
The previous prime is 4431313414039. The next prime is 4431313414051. The reversal of 4431313414041 is 1404143131344.
It is not a de Polignac number, because 4431313414041 - 21 = 4431313414039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4431313413993 and 4431313414011.
It is not an unprimeable number, because it can be changed into a prime (4431313414001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 104740510 + ... + 104782808.
It is an arithmetic number, because the mean of its divisors is an integer number (192405780000).
Almost surely, 24431313414041 is an apocalyptic number.
It is an amenable number.
4431313414041 is a deficient number, since it is larger than the sum of its proper divisors (1725671545959).
4431313414041 is a wasteful number, since it uses less digits than its factorization.
4431313414041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51133.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 4431313414041 its reverse (1404143131344), we get a palindrome (5835456545385).
The spelling of 4431313414041 in words is "four trillion, four hundred thirty-one billion, three hundred thirteen million, four hundred fourteen thousand, forty-one".
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