Base | Representation |
---|---|
bin | 10100001001101011101010… |
… | …01010101010111001001010 |
3 | 12210220021222011000210100012 |
4 | 22010311311022222321022 |
5 | 21302011304142333414 |
6 | 234125102122311522 |
7 | 12222343000303661 |
oct | 1204656512527112 |
9 | 183807864023305 |
10 | 44313143324234 |
11 | 1313510a18aa74 |
12 | 4b782260585a2 |
13 | 1b95933195c15 |
14 | ad2aa6353dd8 |
15 | 51ca4719933e |
hex | 284d752aae4a |
44313143324234 has 8 divisors (see below), whose sum is σ = 66508608914820. Its totient is φ = 22143607019296.
The previous prime is 44313143324227. The next prime is 44313143324251. The reversal of 44313143324234 is 43242334131344.
It can be written as a sum of positive squares in 2 ways, for example, as 41209017330625 + 3104125993609 = 6419425^2 + 1761853^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 44313143324191 and 44313143324200.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6482317139 + ... + 6482323974.
Almost surely, 244313143324234 is an apocalyptic number.
44313143324234 is a deficient number, since it is larger than the sum of its proper divisors (22195465590586).
44313143324234 is a wasteful number, since it uses less digits than its factorization.
44313143324234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12964642824.
The product of its digits is 995328, while the sum is 41.
Adding to 44313143324234 its reverse (43242334131344), we get a palindrome (87555477455578).
The spelling of 44313143324234 in words is "forty-four trillion, three hundred thirteen billion, one hundred forty-three million, three hundred twenty-four thousand, two hundred thirty-four".
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