443141212303113 has 4 divisors (see below), whose sum is σ = 590854949737488. Its totient is φ = 295427474868740.

The previous prime is 443141212303103. The next prime is 443141212303123. The reversal of 443141212303113 is 311303212141344.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (443141212303103) and next prime (443141212303123).

It is a cyclic number.

It is not a de Polignac number, because 443141212303113 - 2⁵ = 443141212303081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (443141212303103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73856868717183 + ... + 73856868717188.

It is an arithmetic number, because the mean of its divisors is an integer number (147713737434372).

Almost surely, 2^{443141212303113} is an apocalyptic number.

It is an amenable number.

443141212303113 is a deficient number, since it is larger than the sum of its proper divisors (147713737434375).

443141212303113 is a wasteful number, since it uses less digits than its factorization.

443141212303113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 147713737434374.

The product of its (nonzero) digits is 20736, while the sum is 33.

Adding to 443141212303113 its reverse (311303212141344), we get a palindrome (754444424444457).

The spelling of 443141212303113 in words is "four hundred forty-three trillion, one hundred forty-one billion, two hundred twelve million, three hundred three thousand, one hundred thirteen".