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44316012513 = 314772004171
BaseRepresentation
bin101001010001011100…
…001010111111100001
311020101110101200121210
4221101130022333201
51211224344400023
632205233540333
73126122614443
oct512134127741
9136343350553
1044316012513
1117881263133
1287094146a9
1342432ba216
1422058a2493
151245880593
hexa5170afe1

44316012513 has 4 divisors (see below), whose sum is σ = 59088016688. Its totient is φ = 29544008340.

The previous prime is 44316012511. The next prime is 44316012551. The reversal of 44316012513 is 31521061344.

44316012513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 44316012513 - 21 = 44316012511 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (44316012511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7386002083 + ... + 7386002088.

It is an arithmetic number, because the mean of its divisors is an integer number (14772004172).

Almost surely, 244316012513 is an apocalyptic number.

It is an amenable number.

44316012513 is a deficient number, since it is larger than the sum of its proper divisors (14772004175).

44316012513 is a wasteful number, since it uses less digits than its factorization.

44316012513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14772004174.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 44316012513 its reverse (31521061344), we get a palindrome (75837073857).

The spelling of 44316012513 in words is "forty-four billion, three hundred sixteen million, twelve thousand, five hundred thirteen".

Divisors: 1 3 14772004171 44316012513