Base | Representation |
---|---|
bin | 101001010010000000… |
… | …100011100000011111 |
3 | 11020102010100020202011 |
4 | 221102000203200133 |
5 | 1211234320100421 |
6 | 32210214212051 |
7 | 3126266650033 |
oct | 512200434037 |
9 | 136363306664 |
10 | 44325550111 |
11 | 17886687947 |
12 | 8710654027 |
13 | 424527947b |
14 | 2206c661c3 |
15 | 12466164e1 |
hex | a5202381f |
44325550111 has 4 divisors (see below), whose sum is σ = 44337808512. Its totient is φ = 44313291712.
The previous prime is 44325550099. The next prime is 44325550153. The reversal of 44325550111 is 11105552344.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 44325550111 - 213 = 44325541919 is a prime.
It is a super-2 number, since 2×443255501112 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (44325551111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6123775 + ... + 6131008.
It is an arithmetic number, because the mean of its divisors is an integer number (11084452128).
Almost surely, 244325550111 is an apocalyptic number.
44325550111 is a deficient number, since it is larger than the sum of its proper divisors (12258401).
44325550111 is a wasteful number, since it uses less digits than its factorization.
44325550111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12258400.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 44325550111 in words is "forty-four billion, three hundred twenty-five million, five hundred fifty thousand, one hundred eleven".
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