Base | Representation |
---|---|
bin | 100000010000010101101… |
… | …0000111100010111110001 |
3 | 120200210200121011201022222 |
4 | 1000200223100330113301 |
5 | 1040113023310030340 |
6 | 13232315222210425 |
7 | 635166101132000 |
oct | 100405320742761 |
9 | 16623617151288 |
10 | 4433132111345 |
11 | 145a098561673 |
12 | 5b7206b83a15 |
13 | 26207268ab92 |
14 | 1147c9902c37 |
15 | 7a4b146a8b5 |
hex | 4082b43c5f1 |
4433132111345 has 32 divisors (see below), whose sum is σ = 6204046867200. Its totient is φ = 3039741075840.
The previous prime is 4433132111299. The next prime is 4433132111347. The reversal of 4433132111345 is 5431112313344.
It is not a de Polignac number, because 4433132111345 - 210 = 4433132110321 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is not an unprimeable number, because it can be changed into a prime (4433132111347) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 74951954 + ... + 75011076.
It is an arithmetic number, because the mean of its divisors is an integer number (193876464600).
Almost surely, 24433132111345 is an apocalyptic number.
It is an amenable number.
4433132111345 is a deficient number, since it is larger than the sum of its proper divisors (1770914755855).
4433132111345 is an equidigital number, since it uses as much as digits as its factorization.
4433132111345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102870 (or 102856 counting only the distinct ones).
The product of its digits is 51840, while the sum is 35.
Adding to 4433132111345 its reverse (5431112313344), we get a palindrome (9864244424689).
The spelling of 4433132111345 in words is "four trillion, four hundred thirty-three billion, one hundred thirty-two million, one hundred eleven thousand, three hundred forty-five".
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