Base | Representation |
---|---|
bin | 100000010000111001101… |
… | …1111111110010111010111 |
3 | 120200220211001120121102122 |
4 | 1000201303133332113113 |
5 | 1040123014031324343 |
6 | 13233035353330155 |
7 | 635241115121540 |
oct | 100416337762727 |
9 | 16626731517378 |
10 | 4434344011223 |
11 | 145a65a655a15 |
12 | 5b74a4a0695b |
13 | 26220678a8b9 |
14 | 1148a284d4c7 |
15 | 7a532a57068 |
hex | 408737fe5d7 |
4434344011223 has 4 divisors (see below), whose sum is σ = 5067821727120. Its totient is φ = 3800866295328.
The previous prime is 4434344011213. The next prime is 4434344011267. The reversal of 4434344011223 is 3221104434344.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4434344011223 - 222 = 4434339816919 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4434344011213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 316738857938 + ... + 316738857951.
It is an arithmetic number, because the mean of its divisors is an integer number (1266955431780).
Almost surely, 24434344011223 is an apocalyptic number.
4434344011223 is a deficient number, since it is larger than the sum of its proper divisors (633477715897).
4434344011223 is an equidigital number, since it uses as much as digits as its factorization.
4434344011223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 633477715896.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 4434344011223 its reverse (3221104434344), we get a palindrome (7655448445567).
The spelling of 4434344011223 in words is "four trillion, four hundred thirty-four billion, three hundred forty-four million, eleven thousand, two hundred twenty-three".
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