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4441113114434 = 22220556557217
BaseRepresentation
bin100000010100000011011…
…1110000011011101000010
3120201120021210211200100222
41000220012332003131002
51040230344424130214
613240115202543042
7635600631421403
oct100500676033502
916646253750328
104441113114434
111462513634397
125b8873967a82
13262a44cac309
14114d458639aa
157a7cbe6238e
hex40a06f83742

4441113114434 has 4 divisors (see below), whose sum is σ = 6661669671654. Its totient is φ = 2220556557216.

The previous prime is 4441113114409. The next prime is 4441113114467. The reversal of 4441113114434 is 4344113111444.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 3044100220225 + 1397012894209 = 1744735^2 + 1181953^2 .

It is a junction number, because it is equal to n+sod(n) for n = 4441113114394 and 4441113114403.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1110278278607 + ... + 1110278278610.

Almost surely, 24441113114434 is an apocalyptic number.

4441113114434 is a deficient number, since it is larger than the sum of its proper divisors (2220556557220).

4441113114434 is a wasteful number, since it uses less digits than its factorization.

4441113114434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2220556557219.

The product of its digits is 36864, while the sum is 35.

Adding to 4441113114434 its reverse (4344113111444), we get a palindrome (8785226225878).

The spelling of 4441113114434 in words is "four trillion, four hundred forty-one billion, one hundred thirteen million, one hundred fourteen thousand, four hundred thirty-four".

Divisors: 1 2 2220556557217 4441113114434