444114100221133 has 4 divisors (see below), whose sum is σ = 444202763452380. Its totient is φ = 444025436989888.

The previous prime is 444114100221091. The next prime is 444114100221179. The reversal of 444114100221133 is 331122001411444.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 250183910743209 + 193930189477924 = 15817203^2 + 13925882^2 .

It is a cyclic number.

It is not a de Polignac number, because 444114100221133 - 2⁹ = 444114100220621 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 444114100221095 and 444114100221104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (444114100221733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44331608110 + ... + 44331618127.

It is an arithmetic number, because the mean of its divisors is an integer number (111050690863095).

Almost surely, 2^{444114100221133} is an apocalyptic number.

It is an amenable number.

444114100221133 is a deficient number, since it is larger than the sum of its proper divisors (88663231247).

444114100221133 is an equidigital number, since it uses as much as digits as its factorization.

444114100221133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 88663231246.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 444114100221133 its reverse (331122001411444), we get a palindrome (775236101632577).

The spelling of 444114100221133 in words is "four hundred forty-four trillion, one hundred fourteen billion, one hundred million, two hundred twenty-one thousand, one hundred thirty-three".