Base | Representation |
---|---|
bin | 110010011111100000001100… |
… | …1011000100101011111101011 |
3 | 2011020112211112020202110222122 |
4 | 1210333000121120211133223 |
5 | 431203144224412121303 |
6 | 4212332310053541455 |
7 | 162356436364230551 |
oct | 14477003130453753 |
9 | 2136484466673878 |
10 | 444134404020203 |
11 | 119573385566a86 |
12 | 4199028134488b |
13 | 160a8905025580 |
14 | 7b963113b1bd1 |
15 | 3652e4d5e8e38 |
hex | 193f0196257eb |
444134404020203 has 32 divisors (see below), whose sum is σ = 510939379827072. Its totient is φ = 382421820211200.
The previous prime is 444134404020173. The next prime is 444134404020211. The reversal of 444134404020203 is 302020404431444.
It is a cyclic number.
It is not a de Polignac number, because 444134404020203 - 232 = 444130109052907 is a prime.
It is a super-2 number, since 2×4441344040202032 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (444134404020803) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 548776883 + ... + 549585603.
It is an arithmetic number, because the mean of its divisors is an integer number (15966855619596).
Almost surely, 2444134404020203 is an apocalyptic number.
444134404020203 is a deficient number, since it is larger than the sum of its proper divisors (66804975806869).
444134404020203 is a wasteful number, since it uses less digits than its factorization.
444134404020203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 830855.
The product of its (nonzero) digits is 147456, while the sum is 35.
Adding to 444134404020203 its reverse (302020404431444), we get a palindrome (746154808451647).
The spelling of 444134404020203 in words is "four hundred forty-four trillion, one hundred thirty-four billion, four hundred four million, twenty thousand, two hundred three".
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