444135020452021 has 4 divisors (see below), whose sum is σ = 444142418200492. Its totient is φ = 444127622703552.

The previous prime is 444135020451973. The next prime is 444135020452051. The reversal of 444135020452021 is 120254020531444.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 382391728315921 + 61743292136100 = 19554839^2 + 7857690^2 .

It is a cyclic number.

It is not a de Polignac number, because 444135020452021 - 2⁹ = 444135020451509 is a prime.

It is a super-2 number, since 2×444135020452021² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (444135020452051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3698784180 + ... + 3698904253.

It is an arithmetic number, because the mean of its divisors is an integer number (111035604550123).

Almost surely, 2^{444135020452021} is an apocalyptic number.

It is an amenable number.

444135020452021 is a deficient number, since it is larger than the sum of its proper divisors (7397748471).

444135020452021 is an equidigital number, since it uses as much as digits as its factorization.

444135020452021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7397748470.

The product of its (nonzero) digits is 153600, while the sum is 37.

Adding to 444135020452021 its reverse (120254020531444), we get a palindrome (564389040983465).

The spelling of 444135020452021 in words is "four hundred forty-four trillion, one hundred thirty-five billion, twenty million, four hundred fifty-two thousand, twenty-one".