4443431313445 has 4 divisors (see below), whose sum is σ = 5332117576140. Its totient is φ = 3554745050752.

The previous prime is 4443431313439. The next prime is 4443431313467. The reversal of 4443431313445 is 5443131343444.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3076856285409 + 1366575028036 = 1754097^2 + 1169006^2 .

It is a cyclic number.

It is not a de Polignac number, because 4443431313445 - 2¹³ = 4443431305253 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 444343131340 + ... + 444343131349.

It is an arithmetic number, because the mean of its divisors is an integer number (1333029394035).

Almost surely, 2^{4443431313445} is an apocalyptic number.

It is an amenable number.

4443431313445 is a deficient number, since it is larger than the sum of its proper divisors (888686262695).

4443431313445 is an equidigital number, since it uses as much as digits as its factorization.

4443431313445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 888686262694.

The product of its digits is 1658880, while the sum is 43.

Adding to 4443431313445 its reverse (5443131343444), we get a palindrome (9886562656889).

Subtracting 4443431313445 from its reverse (5443131343444), we obtain a cube (999700029999 = 9999³).

The spelling of 4443431313445 in words is "four trillion, four hundred forty-three billion, four hundred thirty-one million, three hundred thirteen thousand, four hundred forty-five".