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45102031 = 133469387
BaseRepresentation
bin1010110000001…
…1001111001111
310010212102100121
42230003033033
543021231111
64250405411
71055234542
oct254031717
9103772317
1045102031
1123505907
1213130867
139461bc0
145dc0859
153e5d871
hex2b033cf

45102031 has 4 divisors (see below), whose sum is σ = 48571432. Its totient is φ = 41632632.

The previous prime is 45102023. The next prime is 45102053. The reversal of 45102031 is 13020154.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 45102031 - 23 = 45102023 is a prime.

It is a super-2 number, since 2×451020312 = 4068386400649922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 45101996 and 45102014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (45102061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1734681 + ... + 1734706.

It is an arithmetic number, because the mean of its divisors is an integer number (12142858).

Almost surely, 245102031 is an apocalyptic number.

45102031 is a deficient number, since it is larger than the sum of its proper divisors (3469401).

45102031 is a wasteful number, since it uses less digits than its factorization.

45102031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3469400.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 45102031 is about 6715.8045683298. The cubic root of 45102031 is about 355.9579522573.

Adding to 45102031 its reverse (13020154), we get a palindrome (58122185).

The spelling of 45102031 in words is "forty-five million, one hundred two thousand, thirty-one".

Divisors: 1 13 3469387 45102031