Base | Representation |
---|---|
bin | 10100100001010000010001… |
… | …01101100100111110101011 |
3 | 12220202201112111210212002222 |
4 | 22100220020231210332223 |
5 | 21403244023034434301 |
6 | 235545130421144255 |
7 | 12335014542334061 |
oct | 1220501055447653 |
9 | 186681474725088 |
10 | 45123072577451 |
11 | 13417651128660 |
12 | 50891a185b08b |
13 | 1c2411a28c34b |
14 | b1dd7b2a4031 |
15 | 533b4c02231b |
hex | 290a08b64fab |
45123072577451 has 4 divisors (see below), whose sum is σ = 49225170084504. Its totient is φ = 41020975070400.
The previous prime is 45123072577447. The next prime is 45123072577469. The reversal of 45123072577451 is 15477527032154.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 45123072577451 - 22 = 45123072577447 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 45123072577393 and 45123072577402.
It is not an unprimeable number, because it can be changed into a prime (45123072577951) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2051048753510 + ... + 2051048753531.
It is an arithmetic number, because the mean of its divisors is an integer number (12306292521126).
Almost surely, 245123072577451 is an apocalyptic number.
45123072577451 is a deficient number, since it is larger than the sum of its proper divisors (4102097507053).
45123072577451 is a wasteful number, since it uses less digits than its factorization.
45123072577451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4102097507052.
The product of its (nonzero) digits is 8232000, while the sum is 53.
The spelling of 45123072577451 in words is "forty-five trillion, one hundred twenty-three billion, seventy-two million, five hundred seventy-seven thousand, four hundred fifty-one".
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