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4540355052333 = 31513451684111
BaseRepresentation
bin100001000010010001001…
…0000000000001100101101
3121002001110011001110220120
41002010202100000030231
51043342121343133313
613353451010035153
7646013142112332
oct102044220001455
917061404043816
104540355052333
1114a0610073191
12613b4b878ab9
1326c1cc7307a9
14119a7bd54989
157d18985ad23
hex4212240032d

4540355052333 has 4 divisors (see below), whose sum is σ = 6053806736448. Its totient is φ = 3026903368220.

The previous prime is 4540355052301. The next prime is 4540355052349. The reversal of 4540355052333 is 3332505530454.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4540355052333 - 25 = 4540355052301 is a prime.

It is a super-2 number, since 2×45403550523332 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4540355072333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 756725842053 + ... + 756725842058.

It is an arithmetic number, because the mean of its divisors is an integer number (1513451684112).

Almost surely, 24540355052333 is an apocalyptic number.

It is an amenable number.

4540355052333 is a deficient number, since it is larger than the sum of its proper divisors (1513451684115).

4540355052333 is a wasteful number, since it uses less digits than its factorization.

4540355052333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1513451684114.

The product of its (nonzero) digits is 1620000, while the sum is 42.

The spelling of 4540355052333 in words is "four trillion, five hundred forty billion, three hundred fifty-five million, fifty-two thousand, three hundred thirty-three".

Divisors: 1 3 1513451684111 4540355052333