45443533534453 has 4 divisors (see below), whose sum is σ = 45510068723328. Its totient is φ = 45376998345580.

The previous prime is 45443533534447. The next prime is 45443533534471. The reversal of 45443533534453 is 35443533534454.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 45443533534453 - 2⁴¹ = 43244510278901 is a prime.

It is a super-3 number, since 3×45443533534453³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 45443533534394 and 45443533534403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (45443533534433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33267593413 + ... + 33267594778.

It is an arithmetic number, because the mean of its divisors is an integer number (11377517180832).

Almost surely, 2^{45443533534453} is an apocalyptic number.

It is an amenable number.

45443533534453 is a deficient number, since it is larger than the sum of its proper divisors (66535188875).

45443533534453 is an equidigital number, since it uses as much as digits as its factorization.

45443533534453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66535188874.

The product of its digits is 155520000, while the sum is 55.

Subtracting from 45443533534453 its reverse (35443533534454), we obtain a palindrome (9999999999999).

The spelling of 45443533534453 in words is "forty-five trillion, four hundred forty-three billion, five hundred thirty-three million, five hundred thirty-four thousand, four hundred fifty-three".