Base | Representation |
---|---|
bin | 10100101100111001011001… |
… | …11110101111000010111001 |
3 | 12222011222010000110120211202 |
4 | 22112130230332233002321 |
5 | 21431322313412412213 |
6 | 240453010204103545 |
7 | 12405636115050206 |
oct | 1226345476570271 |
9 | 188158100416752 |
10 | 45523113013433 |
11 | 13561275569120 |
12 | 5132826534bb5 |
13 | 1c52a710b77b3 |
14 | b3548a990cad |
15 | 53e262256b58 |
hex | 29672cfaf0b9 |
45523113013433 has 12 divisors (see below), whose sum is σ = 50370888269904. Its totient is φ = 40801765775400.
The previous prime is 45523113013397. The next prime is 45523113013447. The reversal of 45523113013433 is 33431031132554.
It is a de Polignac number, because none of the positive numbers 2k-45523113013433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (45523113213433) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 410425091 + ... + 410535992.
It is an arithmetic number, because the mean of its divisors is an integer number (4197574022492).
Almost surely, 245523113013433 is an apocalyptic number.
It is an amenable number.
45523113013433 is a deficient number, since it is larger than the sum of its proper divisors (4847775256471).
45523113013433 is an equidigital number, since it uses as much as digits as its factorization.
45523113013433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 820961236 (or 820961165 counting only the distinct ones).
The product of its (nonzero) digits is 194400, while the sum is 38.
Adding to 45523113013433 its reverse (33431031132554), we get a palindrome (78954144145987).
The spelling of 45523113013433 in words is "forty-five trillion, five hundred twenty-three billion, one hundred thirteen million, thirteen thousand, four hundred thirty-three".
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